a/2=b/3=c/4 and a+b+c=18.Find c.?
回答 (3)
2016-06-22 7:01 pm
a/2 = b/3 = c/4
Let a = 2k, b = 3k and c = 4k
a + b + c = 18
2k + 3k + 4k = 18
k = 2
c = 4 * 2
c = 8
Let a = 2k, b = 3k and c = 4k
a + b + c = 18
2k + 3k + 4k = 18
k = 2
c = 4 * 2
c = 8
2016-06-22 6:58 pm
Well,
a/2=b/3=c/4
therefore
a = 2/4 c = c/2
b = 3/4 c
that we replace in
a + b + c = 18
c/2 + 3/4 c + c = 18
c * (1/2 + 3/4 + 1) = 18
c * (2/4 + 3/4 + 4/4) = 18
c * 9/4 = 18
c = 4/9 * 18
c = 4 * 18/9
c = 8
hope it' ll help !!
a/2=b/3=c/4
therefore
a = 2/4 c = c/2
b = 3/4 c
that we replace in
a + b + c = 18
c/2 + 3/4 c + c = 18
c * (1/2 + 3/4 + 1) = 18
c * (2/4 + 3/4 + 4/4) = 18
c * 9/4 = 18
c = 4/9 * 18
c = 4 * 18/9
c = 8
hope it' ll help !!
2016-06-22 6:58 pm
b = (3/4)c
a = (1/2)c
a + b + c = 18
(1/2)c + (3/4)c + c = 18
(9/4)c = 18
9c = 72
c = 8
a = (1/2)c
a + b + c = 18
(1/2)c + (3/4)c + c = 18
(9/4)c = 18
9c = 72
c = 8
收錄日期: 2021-04-18 15:10:33
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