Prepare 2.50 M solution of sodium chloride. You only have 0.325 moles of sodium chloride, and must use it all, how many mL must you prepare?
回答 (2)
2016-06-22 4:59 pm
Molarity in M = (No. of moles of solute) / (Volume of solution in L)
Volume of solution in L = (No. of moles of solute) / (Molarity in M) = (0.325 mol) / (2.50 mol/L) = 0.13 L
Volume of solution = 0.13 L = 130 mL
Volume of solution in L = (No. of moles of solute) / (Molarity in M) = (0.325 mol) / (2.50 mol/L) = 0.13 L
Volume of solution = 0.13 L = 130 mL
2016-06-22 4:52 pm
0.325/2.5 = 0.13 L final volume.
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