Chemistry - Chemical Bonds Question?

K is a metal while O is a non-metal, and thus ionic bonds are formed.
There is 1 electron in the outermost shell of each K atom. Each K atom thus loses 1 electron in its outermost shell and becomes a K⁺ ion, which is stable because its outermost shell attains a stable octet.
There are 6 electrons in the outermost shell of each O atom. Each O atom thus gains 2 electrons to become an O²⁻ ion, which is stable because its outermost shell attains a stable octet.
As each K atom loses 1 electron while each O atom gains 2 electrons, numbers of K⁺ and O²⁻ are in the ratio 2 : 1, and thus the formula of the compound is K₂O.
A huge number of K⁺ and O²⁻ are held together in ratio 2 : 1 by ionic bonds.

Both C and H are non-metal, and thus covalent bonds are formed.
There are 4 electrons in the outermost shell of the central C atom, and 1 electron in the outermost shell of each H atom. The C atom share its electrons with the 4 H atoms by forming 4 covalent bonds. Each covalent bond contains 1 shared pair of electrons. Both the central C atom and the 4 H atoms are stable because the outermost shell of the central C atom attains a stable octet while that of each H atom attains a stable doublet.

K atoms have 1 valence e- each before reacting
O atoms have 6 valence e- each before reacting

The O atom needs 8 val. e- to be stable, so it reacts with 2 K atoms. The electrons of the K atoms are transferred to the O atom forming two K(+) ions and one O(2-) ion .. these are attracted to each other (opposite charges attract) to form one unit of K2O ... it is made of ions, so it is an ionic compound. ... Transfer of e- from one atom to another creates ions.
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CH4 is NOT formed by transfer of e-, but by the atoms sharing e-.
Each C has 4 valence e- ... each H has 1 valence e- ... by sharing the electrons they form a covalent bond ... not ions.