Question: A man opens a general store and a book shop. In any one year the probability of a robbery in the general store is 0.10 and the probability of a robbery in the book shop is 0.02. For any one year. What is the probability that:
a. Neither business will be robbed.
b. Either one or the other (but not both) will be robbed.
Explain the answer too please.
Probability?
2016-06-22 10:40 am
回答 (2)
2016-06-22 11:07 am
✔ 最佳答案
a.P(Neither business is robbed)
= P(General store not robbed) × P(Book shop not robbed)
= (1 - 0.10) × (1 - 0.02)
= 0.882
b.
P(Either one shop or the other is robbed)
= 1 - P(Neither business is robbed) - P(Both business are robbed)
= 1 - 0.882 - 0.10 × 0.02
= 0.116
OR:
P(Either one shop or the other is robbed)
= P(General store robbed) × P(Book shop not robbed) + P(Book shop robbed) × P(General store not robbed)
= 0.10 × (1 - 0.02) + 0.02 × (1 - 0.10)
= 0.116
2016-06-22 12:46 pm
a)
P(no robbery on general shop) = 1-0.10 = 0.90
P( no robbery on book shop ) =1-0.02 = 0.98
P( Neither business will be robbed) = (0.90)(0.98) = 0.882
b)
P(store robbed, bookshop not robbed) + P( store not robbed, book shop robbed)
= (0.10)(0.98) + (0.90)(0.02)
= 0. 116
P(no robbery on general shop) = 1-0.10 = 0.90
P( no robbery on book shop ) =1-0.02 = 0.98
P( Neither business will be robbed) = (0.90)(0.98) = 0.882
b)
P(store robbed, bookshop not robbed) + P( store not robbed, book shop robbed)
= (0.10)(0.98) + (0.90)(0.02)
= 0. 116
收錄日期: 2021-04-18 15:10:24
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