how to find percentage of oxygen by weight in HCOOH?
回答 (1)
2016-06-22 10:23 am
In 1 mole of HCOOH :
Weight of O = 16.00 × 2 g = 32.00 g
Total weight = 1.01 × 2 + 12.01 + 16.00 × 2 g = 46.03 g
Percentage of O by weight = (32.00/46.03) × 100% = 69.5%
Weight of O = 16.00 × 2 g = 32.00 g
Total weight = 1.01 × 2 + 12.01 + 16.00 × 2 g = 46.03 g
Percentage of O by weight = (32.00/46.03) × 100% = 69.5%
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