The reduction of a metallic oxide is represented by this generic equation
MxOy(s)+yH2(g)→xM(s)+yH2O(g)
where M represents the symbol for the metal and x and y are the subscripts in the formula.
Consider the data in the following table:
Substance ΔH∘f (kJ/mol)
V2O5(s) −1550.6
H2(g)H2(g) 0
V(s) 0
H2O(g) −241.82
Calculate ΔH∘rxn for the reduction for V2O5.
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2016-06-22 4:55 am
回答 (1)
2016-06-22 6:48 am
✔ 最佳答案
V₂O₅(s) + 5H₂(g) → 2V(s) + 5H₂O(g)ΔH°rxn
= 2 ΔH°f[V(s)] + 5 ΔHf°[H₂O(g)] - ΔH°[V₂O₅(s)] - 5 ΔH°f[H₂(g)]
= [2 × 0 + 5 × (-241.82) - (-1550.6) + 5 × (0)] kJ
= +341.5 kJ
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