What was its initial temperature?
2016-06-21 6:17 pm
After absorbing 1.440 kJ of energy as heat, the temperature of a 0.500-kg block of copper is 40. °C. What was its initial temperature? (The specific heat capacity of copper is 0.385 J/g ⋅ K.)
回答 (1)
2016-06-21 6:33 pm
Let T be the initial temperature.
Heat absorbed = m c ΔT
1.440 kJ = (0.500 kg) × (0.385 kJ/kg K) × [(40 - T) K]
40 - T = 1.440 / (0.500 × 0.385)
T = 40 - [1.440 / (0.500 × 0.385)]
T = 32.5
Initial temperature = 32.5°C
Heat absorbed = m c ΔT
1.440 kJ = (0.500 kg) × (0.385 kJ/kg K) × [(40 - T) K]
40 - T = 1.440 / (0.500 × 0.385)
T = 40 - [1.440 / (0.500 × 0.385)]
T = 32.5
Initial temperature = 32.5°C
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