734mL of a 1.13M calcium sulfate solution is diluted with 2.56L of water. What is the new concentration in molarity?
回答 (2)
2016-06-21 5:22 pm
Before dilution: M₁ = 1.13 M, V₁ = 734 mL
After dilution: M₂ = ? M, V₂ = (734 + 2560) mL = 3294 mL
M₁V₁ = M₂V₂
M₂ = M₁ × (V₁/V₂)
New concentration, M₂ = (1.13 M) × (734/3294) = 0.252 M
After dilution: M₂ = ? M, V₂ = (734 + 2560) mL = 3294 mL
M₁V₁ = M₂V₂
M₂ = M₁ × (V₁/V₂)
New concentration, M₂ = (1.13 M) × (734/3294) = 0.252 M
2016-06-21 5:10 pm
No.
收錄日期: 2021-04-18 15:10:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160621090935AAnrIF8