Chemistry Help?
2016-06-21 2:56 pm
A balloon containing 0.148 mol Ne gas has a volume of 1.9 L at 1.9 atm and 28°C. How many grams of neon should be added to the balloon to increase the volume to 3.4 L at the same pressure and temperature?
回答 (1)
2016-06-21 3:11 pm
PV = nRT
When P, T and R are constant.
n/V = P/(RT) = constant
Hence, n₁/V₁ = n₂/V₂
n₂ = n₁ × (V₂/V₁)
n₂ - n₁ = n₁ × (V₂/V₁) - n₁
Number of moles of Ne added, n₂ - n₁ = [0.148 × (3.4/1.9) - 0.148] mol
Mass of Ne added = (20.18 g/mol) × {[0.148 × (3.4/1.9) - 0.148] mol} = 2.36 g
When P, T and R are constant.
n/V = P/(RT) = constant
Hence, n₁/V₁ = n₂/V₂
n₂ = n₁ × (V₂/V₁)
n₂ - n₁ = n₁ × (V₂/V₁) - n₁
Number of moles of Ne added, n₂ - n₁ = [0.148 × (3.4/1.9) - 0.148] mol
Mass of Ne added = (20.18 g/mol) × {[0.148 × (3.4/1.9) - 0.148] mol} = 2.36 g
收錄日期: 2021-04-18 15:17:44
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https://hk.answers.yahoo.com/question/index?qid=20160621065637AAQZHmc