Find the x coordinate, h, of the vertex of the graph of the following function:
f(x) = -4x2 - 3
How do I solve this?
2016-06-21 1:56 pm
回答 (2)
2016-06-21 2:00 pm
(h, k) is the vertex of f(x) = a(x - h)² + k
The given function is f(x) = -4x² - 3 cannot be rewritten as f(x) = -4(x - 0)² - 3
The vertex of the f(x) is (0, -3)
The x-coordinate of the vertex, h = 0
The given function is f(x) = -4x² - 3 cannot be rewritten as f(x) = -4(x - 0)² - 3
The vertex of the f(x) is (0, -3)
The x-coordinate of the vertex, h = 0
2016-06-21 2:43 pm
y = ax^2 + bx + c is the parabola
y = -4x^2+0x-3
x-coordinate of vertex is -b/2a
= -(0) / (2)(-4)
= -0 / (2)(-4) = 0
y = -4x^2+0x-3
x-coordinate of vertex is -b/2a
= -(0) / (2)(-4)
= -0 / (2)(-4) = 0
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