NH4NO3=N2O+2H2O 1. how many moles of ammonium nitrate are present in 0.8g of the solid?

👨🏻‍🏫 學術台化學

[匿名]

2016-06-21 11:29 am

回答 (1)

fooks

2016-06-21 11:49 am

✔ 最佳答案

Molar mass of NH₄NO₃ = (14 + 1×4 + 16×3) g/mol = 80 g/mol

No. of moles of NH₄NO₃ = (0.8 g) / (80 g/mol) = 0.01 mol

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