The length of a rectangle is twice it's width. The perimeter is 36cm? Solve? Best answer avaliable?

We can let the length of the rectangle be x, and the width of the rectangle be y.

The length of the rectangle is twice it s width means:
x = 2y ...(1)

The perimeter is 36cm means:
x + x + y + y = 36
2x + 2y = 36 ...(2)

Subsituting (1) into (2) gives us:
2(2y) + 2y = 36
4y + 2y = 36
6y = 36
y = 6cm

If we put y=6 into (1), we get:
x = 2(6)
x = 12 cm

Hence the length of the rectangle is 12 cm and the width is 6 cm.

LET THE WIDTH BE X cm

THEN THE LENGTH WILL BE 2X cm

PERIMETER = 2 ( LENGTH + WIDTH )

36 = 2 ( 2X + X )

3X= 18

X = 6

WIDTH =6 cm LENGTH = 12 cm ANSWER

Let w cm be the width.
Then, the length = 2w cm

Perimeter (in cm) :
2 (w + 2w) = 36
6w = 36
w = 6
2w = 12

The length is 12 cm and the width is 6 cm.

12" length
6" width

The length of a rectangle is twice it's width.
The perimeter is 36 cm.
2(2w + w) = 36
3w = 18
The length of the rectangle is 12 cm
and its width is 6 cm.

x=2y
so 4 sides are: x,2x,x,2x
sum of 4 sides: 6x
perimerter=sum of 4 sides= 6x=36
x=6