Chemistry help?
2016-06-21 7:37 am
A gas X dissociates on heating to set up the equilibrium : X(g) <-----> Y(g) + Z(g). A quantity of X was heated at constant pressure p at a certain temperature. The equilibrium partial pressure of X was found to be (1/7)p. What is the equilibrium constant Kp at this temperature ?
回答 (2)
2016-06-21 7:44 am
✔ 最佳答案
X(g) ⇌ Y(g) + Z(g)Initial :
The mole fraction of X = 1
The mole fraction of Y = The mole fraction of Z = 0
At equilibrium :
The mole fraction of X = (1/7)p / p = 1/7
Then, The mole fraction of Y = The mole fraction of Z = [1 - (1/7)] / 2 = 3/7
Partial pressures :
P(X) = (1/7)p, P(Y) = P(Z) = (3/7)p
Kp = P(Y) P(Z) / P(X) = [(3/7)p]² / [(1/7)p] = 1.29p
2016-06-21 8:10 am
hate chemistry
收錄日期: 2021-04-18 15:08:21
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https://hk.answers.yahoo.com/question/index?qid=20160620233740AAB0OCE