0.025 mol of oxybenzone is fully excited via the absorption of photons with wavelength of 314 nm. How much energy, in kJ, is absorbed?

2016-06-21 4:12 am

回答 (1)

2016-06-21 9:07 am
Energy
= n h ν
= N h c / λ
= [0.025 × (6.022 × 10²³)] × (6.626 × 10⁻³⁴ J s) × (3 × 10⁸ m/s) / (314 × 10⁻⁹ m)
= 9350 J
= 9.35 kJ


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