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2016-06-20 11:08 pm
A chunk of CO2 sublime into a large flexible rubber balloon. The solid CO2 has a mass of 28.8g. All of the CO2 ends up in the balloon. At temperature of 22 degrees Celsius and a pressure of 742 mm Hg what is the volume of the balloon?
回答 (2)
2016-06-20 11:16 pm
P = (742/760) atm
V = ? L
n = (28.8 g) / [(12.01 + 16.00×2) g/mol] = (28.8/44.01) mol
R = 0.0821 atm L / (mol K)
T = (273 + 22) K = 295 K
PV = nRT
V = nRT/P
Volume, V = (28.8/44.01) × 0.0821 × 295 / (742/760) L = 16.2 L
V = ? L
n = (28.8 g) / [(12.01 + 16.00×2) g/mol] = (28.8/44.01) mol
R = 0.0821 atm L / (mol K)
T = (273 + 22) K = 295 K
PV = nRT
V = nRT/P
Volume, V = (28.8/44.01) × 0.0821 × 295 / (742/760) L = 16.2 L
2016-06-20 11:12 pm
V = nRT / P = (28.8 g CO2 / (44.00964 g CO2/mol)) x (62.36367 L mmHg/K mol) x (22 + 273) K / (742 mmHg) =
16.2 L
16.2 L
收錄日期: 2021-04-18 15:09:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160620150837AASi7M7