A 26 kg child slides down from the top of a 2.07 m slipper slide. If she reaches the bottom with a speed of 1.17 m/s,how much thermal energy?
回答 (2)
2016-06-20 10:55 pm
Take g = 9.81 m/s²
Loss of P.E. = (Work done) + (Gain of K.E.)
m g h = (Work done) + (1/2) m v²
Work done = m g h - (1/2) mv² = 26 × 9.81 × 2.07 - (1/2) × 26 × 1.17² = 510 J
Work done is converted to thermal energy.
Thermal energy = 510 J
Loss of P.E. = (Work done) + (Gain of K.E.)
m g h = (Work done) + (1/2) m v²
Work done = m g h - (1/2) mv² = 26 × 9.81 × 2.07 - (1/2) × 26 × 1.17² = 510 J
Work done is converted to thermal energy.
Thermal energy = 510 J
2016-06-20 10:44 pm
thermal energy? That question is unanswerable.
收錄日期: 2021-04-18 15:13:32
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