Prove that cosX=cotX/cscC using identities?
回答 (3)
2016-06-20 10:30 pm
L.H.S.
= cos(x)
= [cos(x) / sin(x)] * sin(x)
= [cos(x) / sin(x)] / [1 / sin(x)]
= cot(x) / csc(x)
= R.H.S.
Then, cos(x) = cot(x) / csc(x)
= cos(x)
= [cos(x) / sin(x)] * sin(x)
= [cos(x) / sin(x)] / [1 / sin(x)]
= cot(x) / csc(x)
= R.H.S.
Then, cos(x) = cot(x) / csc(x)
2016-06-20 10:30 pm
RHS
cot X / csc X
= (cos X / sin X) / ( 1 / sin X)
= cos X ... QED
cot X / csc X
= (cos X / sin X) / ( 1 / sin X)
= cos X ... QED
2016-06-20 10:29 pm
cot=cos/sin
csc=1/sin
csc=1/sin
收錄日期: 2021-04-18 15:07:31
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