An radioactive element "P" with mass number 238 and atomic number 92 undergoes alpha decay once and after that its undergoes beta decay twice. What is the mass number and atomic number of this new element
Mass number = 238 and atomic number = 92
Mass number = 234 and atomic number = 90
Mass number= 234 and atomic number =92
Mass number = 238 and atomic number = 90
Please help me?
2016-06-20 8:01 am
回答 (1)
2016-06-20 8:20 am
Denote the new element as "X(Z=x,A=y)".
P(Z=92,A=238) → X(Z=x,A=y) + α-particle(Z=2,A=4) + 2β-particle(Z=-1, A=0)
The total mass number (A) is unchanged :
238 = y + 4 + 2*0
y = 234
The total atomic number (Z) is unchanged :
92 = x + 2 + 2*(-1)
x = 92
...... The answer is : Mass number = 234 and atomic number = 92
P(Z=92,A=238) → X(Z=x,A=y) + α-particle(Z=2,A=4) + 2β-particle(Z=-1, A=0)
The total mass number (A) is unchanged :
238 = y + 4 + 2*0
y = 234
The total atomic number (Z) is unchanged :
92 = x + 2 + 2*(-1)
x = 92
...... The answer is : Mass number = 234 and atomic number = 92
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