Find dy when x=3 and dx =0.1 y = x^4 - 4x^3 + 3x^2 +4x - 9?

y = x⁴ - 4x³ + 3x² + 4x - 9
dy = (4x³ - 12x² + 6x + 4) dx

When x = 3 and dx = 0.1 :
dy = (4 * 3³ - 12 * 3² + 6 * 3 + 4) * 0.1
dy = 2.2

dy/dx=4x^3-12x^2+6x+4