Find dy when x=3 and dx =0.1 y = x^4 - 4x^3 + 3x^2 +4x - 9?
回答 (2)
2016-06-20 5:21 am
✔ 最佳答案
y = x⁴ - 4x³ + 3x² + 4x - 9dy = (4x³ - 12x² + 6x + 4) dx
When x = 3 and dx = 0.1 :
dy = (4 * 3³ - 12 * 3² + 6 * 3 + 4) * 0.1
dy = 2.2
2016-06-20 5:09 am
dy/dx=4x^3-12x^2+6x+4
收錄日期: 2021-04-18 15:08:06
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