What is the number of atoms of Na ions in 25.0ml of 0.350 M Na2CO3?
So you convert to liters and use the M conversion and then I got stuck I know somewhere along the way you use A's #.
Can someone help me with chemistry please?? I got stuck after using the M conversion.?
2016-06-17 4:34 pm
回答 (1)
2016-06-17 4:56 pm
No. of moles of Na₂CO₃ = MV = (0.350 mol/L) × (25/1000 L) = 0.00875 mol
1 mole of Na₂CO₃ contains 2 moles of Na⁺ ions.
No. of moles of Na⁺ ions = (0.00875 mol) × 2 = 0.0175 mol
1 mole of Na⁺ ions contains 6.022 × 10²³ Na⁺ ions.
No. of Na⁺ ions = (6.022 × 10²³ /mol) (0.0175 mol) = 1.05 × 10²²
1 mole of Na₂CO₃ contains 2 moles of Na⁺ ions.
No. of moles of Na⁺ ions = (0.00875 mol) × 2 = 0.0175 mol
1 mole of Na⁺ ions contains 6.022 × 10²³ Na⁺ ions.
No. of Na⁺ ions = (6.022 × 10²³ /mol) (0.0175 mol) = 1.05 × 10²²
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