What is normality of a Ca(OH)2 solution, if 45.0 mL of this solution is titrated completely with 25.7 mL of 0.150 N acid?

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[匿名]

2016-06-16 7:31 pm

回答 (1)

fooks

2016-06-16 7:47 pm

No. of eq. of Ca(OH)₂ = No. of eq. of acid

N[Ca(OH)₂] × (45/1000 L) = (0.150 N) × (25.7/1000)

N[Ca(OH)₂] = 0.150 × 25.7 / 45.0 N = 0.0857 N

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