Using the equation, 4Fe + 3O2 --> 2Fe2O3, if 8 moles of iron and oxygen from the air were available, how many moles of iron (III) oxide would be produced?
Not quite sure how to go about solving this...any guidance would be great.
Stoichiometry help (looking for an explanation please)?
2016-06-16 5:57 pm
回答 (1)
2016-06-16 6:03 pm
✔ 最佳答案
4Fe + 3O₂ → 2Fe₂O₃O₂ in air is the excess reactant, and Fe is the limiting reactant.
According to the equation, mole ratio Fe : Fe₂O₃ = 4 : 2 = 2 : 1
No. of moles of Fe reacted = 8 mol
No. of moles of Fe₂O₃ produced = (8 mol) × (1/2) = 4 mol
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