What is the slope of a line that is perpendicular to the line y = x + 4? The slope of the line is?

Y=mx+B (where m represents the magnitude of our slope x)

Our current line is: y = x + 4 (this means m is 1)

But we want to find the perpendicular slope-- which will be the negative reciprocals of m

So the slope of the line perpendicular would be -1

Side note if our m value was say 2/5
then the slope of the line perpendicular would be -5/2 (negative reciprocal)

In the future if you need help in calc 1 and beyond
YouTube Channel: Screened-Instructor
(I'm planning on making an Alg 1 & 2 section this month)

Hope that helps!

Let m be the slope of the unknown line.

Slope of the line (y = x + 4) = 1

As the two lines are perpendicular, the product of their slope = -1
m * 1 = -1
m = -1

The slope of the unknown line = -1

You have the equation y=mx+b known as slope intercept form. m, the number multiplied by x, is your slope and b, the number added to mx, is your y-intercept.
In this equation mx is written as x so the only number m could be is 1, therefor your slope is 1 and your line is a straight line at a 45 degree angle
Trust me, I'm a Math tutor