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[匿名]

2016-06-16 4:37 pm

What is the total volume of all gases that are produced when 32.0 mL of reacts as shown in the reaction below. Assume standard temp and pressure. (d=1.60 g/mL, molar mass=227.10 g/mol)

4C3H5(NO3)3(l) --> 6N2(g) + O2(g) + 12CO2(g) + 10H2)(g)

回答 (1)

fooks

2016-06-16 5:06 pm

✔ 最佳答案

4C₃H₅(NO₃)₃(l) → 6N₂(g) + O₂(g) + 12CO₂(g) + 10H₂O(g)
4 moles of C₃H₅(NO₃)₃(l) produces 29 moles of gaseous products.

Mass of C₃H₅(NO₃)₃(l) = (1.60 g/mL) × (32.0 mL) = 51.2 g
No. of moles of C₃H₅(NO₃)₃(l) = (51.2 g) / (227.10 g/mol) = (51.2/227.10) mol
No. of moles of gaseous products = [(51.2/227.10) mol] × (29/4)

Molar volume of gas = 22.4 L/mol
Total volume of gaseous products = [(51.2/227.10) mol] × (29/4) × (22.4 L/mol) = 36.6 L

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