One trig problem?

2016-06-15 1:51 pm

5cot^2(x)=5. Find all solutions in the interval [0,2pi)

回答 (3)

2016-06-15 1:56 pm

5 cot²(x) = 5

cot²(x) = 1

cot(x) = 1 or cot(x) = -1

x = π/4, π + (π/4) or x = π - (π/4), 2π - (π/4)

x = π/4, 3π/4, 5π/4, 7π/4

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2016-06-15 1:53 pm

5cot²(x) = 5
cot²(x) = 1
cot(x) = ±1
cos(x)/sin(x) = ±1
cos(x) = ±sin(x)
x = π/4, 3π/4, 5π/4, 7π/4

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2016-06-15 4:05 pm

tan²x = 1
tan x = ± 1
x = π/4 , 3π/4 , 5π/4 , 7π/4

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