im trying tosolve e^x=12 and 11^-6y=5 for the first part i got 2.8 but im not sure how to solve for y, please help!?

e^x = 12
ln(e^x) = ln(12)
x ln(e) = ln(12)
x = ln(12)


====
11^(-6y) = 5
log[11^(-6y)] = log(5)
-6y log(11) = log(5)
y = -log(5)/[6log(11)]

e^(x) = 12

Ln[e^(x)] = Ln(12)

x.Ln(e) = Ln(12)

x = Ln(12)

x ≈ 2.485


11^(- 6y) = 5

Ln[11^(- 6y)] = Ln(5)

- 6y.Ln(11) = Ln(5)

- 6y = Ln(5)/Ln(11)

y = - (1/6).Ln(5)/Ln(11)

y ≈ - 0.11186

I'm assuming you meant 11^(-6y) = 5.

11^(-6y) = 5
log₁₁(11^(-6y)) = log₁₁(5)
-6y = log₁₁(5)
y = -⅙log₁₁5
 = log₁₁(1/5^⅙)
 ≅ -0.1119