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Please Help with this question !! How many moles of NaNO3 are produced when 50.0 mL of 2.02 M NaOH is added to 50.0 mL of 2.00 M HNO3?
How many moles of NaNO3 are produced when 50.0 mL of 2.02 M NaOH is added to 50.0 mL of 2.00 M HNO3?
回答 (1)
2016-06-15 3:32 am
NaOH + HNO₃ → NaNO₃ + H₂O
Mole ratio NaOH : HNO₃ = 1 : 1
Initial no. of moles of NaOH = (2.02 mol/L) × (50/1000 L) = 0.101 mol
Initial no. of moles of HNO₃ = (2.00 mol/L) × (50/1000 L) = 0.100 mol < 0.101 mol
Hence, HNO₃ is the limiting reactant (completely reacts).
According to the equation, mole ratio HNO₃ : NaNO₃ = 1 : 1
No. of moles of HNO₃ reacted = 0.100 mol
No. of moles of NaNO₃ produced = 0.100 mol
Mole ratio NaOH : HNO₃ = 1 : 1
Initial no. of moles of NaOH = (2.02 mol/L) × (50/1000 L) = 0.101 mol
Initial no. of moles of HNO₃ = (2.00 mol/L) × (50/1000 L) = 0.100 mol < 0.101 mol
Hence, HNO₃ is the limiting reactant (completely reacts).
According to the equation, mole ratio HNO₃ : NaNO₃ = 1 : 1
No. of moles of HNO₃ reacted = 0.100 mol
No. of moles of NaNO₃ produced = 0.100 mol
收錄日期: 2021-04-18 14:59:56
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