How many moles of MgCl2 are present in 78.3g of MgCl2?

👨🏻‍🏫 學術台化學

Josh

2016-06-15 3:19 am

回答 (1)

fooks

2016-06-15 3:21 am

Molar mass of MgCl₂ = (24.31 + 35.45×2) g/mol = 95.21 g/mol

No. of moles of MgCl₂ = (78.3 g) / (95.21 g/mol) = 0.822 mol

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