How many grams of NH3 can be formed from 0.492 moles of N2?
回答 (2)
2016-06-15 3:41 am
N₂ + 3H₂ → 2NH₃
mole ratio N₂ : NH₃ = 1 : 2
No. of moles of NH₃ = (0.492 mol) × 2 = 0.984 mol
Molar mass of NH₃ = (14.01 + 1.008×3) g/mol = 17.03 g/mol
Mass of NH₃ = (17.03 g/mol) × (0.984 mol) = 16.8 g
mole ratio N₂ : NH₃ = 1 : 2
No. of moles of NH₃ = (0.492 mol) × 2 = 0.984 mol
Molar mass of NH₃ = (14.01 + 1.008×3) g/mol = 17.03 g/mol
Mass of NH₃ = (17.03 g/mol) × (0.984 mol) = 16.8 g
2016-06-15 3:41 am
N2 + 3H2 ⇄ 2NH3
0.492 mol N2 x 2/1 = 0.984 mol NH3
0.984 mol x 17.031 g/mol = 16.8 g NH3
0.492 mol N2 x 2/1 = 0.984 mol NH3
0.984 mol x 17.031 g/mol = 16.8 g NH3
收錄日期: 2021-04-18 15:04:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160614191839AAXXsSu