Chemistry Question Help! How many grams in 1.20 x 10^22molecules of CCl4 ?
回答 (1)
2016-06-15 1:41 am
1 mole of CCl₄ contains 6.022 × 10²³ CCl₄ molecules.
No. of moles of CCl₄ = (1.20 × 10²²) / (6.022 × 10²³ /mol) = 0.0199 mol
Molar mass of CCl₄ = (12.01 + 35.45×4) g/mol = 153.81 g/mol
Mass of CCl₄ = (153.81 g/mol) × (0.0199 mol) = 3.06 g
No. of moles of CCl₄ = (1.20 × 10²²) / (6.022 × 10²³ /mol) = 0.0199 mol
Molar mass of CCl₄ = (12.01 + 35.45×4) g/mol = 153.81 g/mol
Mass of CCl₄ = (153.81 g/mol) × (0.0199 mol) = 3.06 g
收錄日期: 2021-04-18 15:04:32
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