How much CaCl2 do you need to make 500 mL of 1 M of CaCl2?

first..
.. 1 M means 1 mole CaCl2 / 1 L

then via dimensional analysis..

.. 500mL.. .. 1L.. .. ..1 mol CaCl2.. .. 110.98g CaCl2
.. ---- ---- x ---- ----- x ---- ---- --- ---- x ---- ---- ---- ---- --- = 55.5g CaCl2
.. .. . 1.. .. .1000mL... ... ..1 L.. .... ... .. 1 mol CaCl2

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Mukherjee.... geez.

this is incorrect
.. Molecular weight of CaCl2 is 40 + 2 ( 35.5 ) = 40 + 71 = 111 grammol
why?
.. (1) CaCl2 is not a molecular substance. it has a "formula mass"
.. (2) molecular weight does not have units "grammol". it has units of weight (mass) / molecule
.. (3) molar mass has units mass / mol
.. (4) the MASS of 1 "gram mole" of CaCl2 is 111 grams... not 111 grammol

this statement is incorrect
.. "since 1 M solution of CaCl2 corresponds to 111 gram mol of CaCl2 in 1 Liter solution "
why?
.. (5) 1 M solution means 1 MOLE of solute / Liter solution...
.. ... ..for CaCl2 that corresponds to 111g.. .. not 111 gram mol
.. (6) it's either 1 gram mole.. or 111 grams... NOT 111 "gram mole"
.. .. . 111 grammole of CaCl2 is 111 moles of CaCl2... 12,321g of CaCl2
... . ..I don't believe that's what you meant!

this statement is gibberishy
.. 500 ml is 500 ml / 1000 ml /1 Liter = 0.5 Liter
use ( ) next time better yet, do this
.. 500mL = 500mL x (1L / 1000mL) = 0.5 L

this statement is more gibberish
.. " therefore 0.5 Liter of 1 M CaCl2 solution would require 1/2 of 1 M
.. .. solution which is 111 gram CaCl2/ 2"
why?
.. (7).. 1/2 of 1 M solution = what? 0.5M solution?
what you should have written is
.. "the mass of CaCl2 in 0.5L of 1M solution = 1/2 the mass of CaCl2 that is
.. .. in 1L of 1M solution
but even that is a roundabout way to solve the problem.

My suggestion to you.
.. (a) get moles, molar mass, molecular mass, atomic mass, mass vs weight straight in your
.. . . .head before answering anymore of these chemistry questions.
.. (b) you need to learn dimensional analysis.. and sig figs.
.. (c) you would benefit from a remedial chemistry class.

Molar mass of CaCl2 is 110.9840 g/mol
Mol CaCl2 required = 1mol/L * 0.5L = 0.5 mol
Mass CaCl2 required = 0.5*110.9840 = 55.492g CaCl2 required.

No. of moles of CaCl₂ = (1 mol/L) × (500/1000 L) = 0.5 mol

Molar mass of CaCl₂ = (40.08 + 35.45×2) g/mol = 110.98 g/mol
Mass of CaCl₂ needed = (110.98 g/mol) × (0.5 mol) = 55.5 g

Molar mass of CaCl2 is 111
so
1000 ml needs 111 g to make 1 M
then
500 ml needs 111 x 500 / 1000 to make 1 M
= 55.5 g

Mass CaCl2 needed = 0.500 L * 1 mol/L * 110.98 g CaCl2/1 mol = 55.5 g

If 10.0g of CaCl2 and 10.0g of NaCl are dissolved in 100.0mL of solution, what is the concentration of chloride ions? (the molar mass of CaCl2 is 111.0g/mol; the molar mass of NaCl is 58.44g/mol. I found individual molar mass of: Ca-40.08 Cl-35.45 Na-22.99 So I divided 10g ...

Use this equation M means morality (M= mole/volume) substitute the givens make sure to convert ml to L if the answer needed is in grams then (molarmass×mole) gives you the amount in grams.peace

55.49 grams CaCl2

55.49g

1M means 1 mole per litre (mol dm^-3)
So 1 mole of calcium chloride is dissolved in sufficient water to make 1 litre.
500 mL is half (0.5)(1/2) litre.

So dissolve half a mole of calcium chloride and add sufficient water to make 500 mL .

Mr(CaCl2) = 40 + (2x 35.5) = 111
mass(CaCl2) = 0.5 moles x 111 = 55.5 g.

So dissolve 55.5 g CaCl2 in say 250 mL of water. When dissolved add sufficient water to make 500 mL .

NB Adding 55.5g to 250mL will increase the volume because the dry mass of CaCl2 will also have a volume. .

Molecular weight of CaCl2 is 40 + 2 ( 35.5 ) = 40 + 71 = 111 grammol , since 1 M solution of CaCl2 corresponds to 111 gram mol of CaCl2 in 1 Liter solution and 500 ml is 500 ml / 1000 ml /1 Liter = 0.5 Liter ; therefore 0.5 Liter of 1 M CaCl2 solution would require 1/2 of 1 M solution which is 111 gram CaCl2/ 2 = 55.5 grams of CaCl2