Find the equation of the line through (-7,4) whose intercept are numerically equal of opposite sides?
回答 (3)
2016-06-14 4:58 am
Let a be the x-intercept.
Then, y-intercept = a
The equation of the line in intercept form :
(x/a) + (y/a) = 1
x + y = a
The line passes through (-7, 4).
Put x = -7 and y = 4 into the equation of the line :
-7 + 4 = a
a = -3
Then, the equation of the line is :
x + y = -3
x + y + 3 = 0
Then, y-intercept = a
The equation of the line in intercept form :
(x/a) + (y/a) = 1
x + y = a
The line passes through (-7, 4).
Put x = -7 and y = 4 into the equation of the line :
-7 + 4 = a
a = -3
Then, the equation of the line is :
x + y = -3
x + y + 3 = 0
2016-06-14 5:48 am
line through (-7,4) intersects both axes.
It is in Q2.
So the intercepts are (-k,0) and (0,k).
Slope = 1
Y intercept = k
y = x + k
Substitute (-7,4) in the equation.
4 = -7 + k
k = 11
y = x + 11
x = 0, y = 11 (0,11)
y = 0, x = -11 (-11,0)
4 = -7 + 11
so (-7,4) satisfies y = x + 11
It is in Q2.
So the intercepts are (-k,0) and (0,k).
Slope = 1
Y intercept = k
y = x + k
Substitute (-7,4) in the equation.
4 = -7 + k
k = 11
y = x + 11
x = 0, y = 11 (0,11)
y = 0, x = -11 (-11,0)
4 = -7 + 11
so (-7,4) satisfies y = x + 11
2016-06-14 5:12 am
WTF is that supposed to mean?
收錄日期: 2021-04-18 15:08:16
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