N2H4(l) + O2(g) -> N2(g) + 2H2O(l)
Delta H=-623.25kJ/mol
What is the enthalpy change associated with the production of 250L of Nitrogen at STP?
Enthalpy change?
2016-06-13 2:55 pm
回答 (1)
2016-06-13 6:47 pm
✔ 最佳答案
1 mole of N₂ occupies a volume of 22.4 L at STP.No. of moles of N₂ = (250 L) / (22.4 L/mol) = 11.16 mol
N₂H₄(l) + O₂(g) → N₂(g) + 2H₂O(l) ...... ΔH = -623.25 kJ/mol
The production of 1 mole of N₂ associated with -623.25 kJ of enthalpy change.
The enthalpy change associated with the production of 250 L of nitrogen at STP
= (-623.25 kJ/mol) × (11.16 mol)
= -6955 kJ
收錄日期: 2021-04-18 14:58:21
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