How many molecules of (NH4)2SO4 in of 0.00345 moles?
回答 (1)
2016-06-13 10:04 am
1 mole of (NH₄)₂SO₄ contains 6.022 × 10²³ (NH₄)₂SO₄ molecules.
No. of (NH₄)₂SO₄ molecules = (0.00345 mol) × (6.022 × 10²³ /mol) = 2.08 × 10²¹
((NH₄)₂SO₄ is an ionic compound. It is better to use the term "formula units" instead of "molecules".)
No. of (NH₄)₂SO₄ molecules = (0.00345 mol) × (6.022 × 10²³ /mol) = 2.08 × 10²¹
((NH₄)₂SO₄ is an ionic compound. It is better to use the term "formula units" instead of "molecules".)
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