chemistry> solution concentration: molarity?
2016-06-13 9:40 am
a solution is prepared by dissolving .5842 g oxaclic acid (H2C2O4) is enough water to make 100.0 mL of solution. A 10.00 mL aliquot (portion) iof this solution is then diluted to a final volume of 250 mL. what is the final molarity of the oxalic acid solution?
回答 (1)
2016-06-13 9:48 am
Molar mass of H₂C₂O₄ = (1.008×2 + 12.01×2 + 16.00×4) g/mol = 90.04 g/mol
No. of moles of H₂C₂O₄ = (0.5842 g) / (90.04 g/mol) = 0.006488 mol
Molarity of H₂C₂O₄ = (0.006488 mol) / (100.0 mL) = 0.06488 M
Dilution :
M₁V₁ = M₂V₂
(0.06488 M) × (10 mL) = M₂ × (250 mL)
Final molarity of H₂C₂O₄ = (0.06488 M) × (10/250) = 0.002595 M
No. of moles of H₂C₂O₄ = (0.5842 g) / (90.04 g/mol) = 0.006488 mol
Molarity of H₂C₂O₄ = (0.006488 mol) / (100.0 mL) = 0.06488 M
Dilution :
M₁V₁ = M₂V₂
(0.06488 M) × (10 mL) = M₂ × (250 mL)
Final molarity of H₂C₂O₄ = (0.06488 M) × (10/250) = 0.002595 M
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