A 2.00 M aqueous solution of LiCl has a density of 1.0450 g/mL. If the total mass of the solution is 51.0 g, Mass of LiCl and Mass of H20?
回答 (2)
2016-06-18 1:24 pm
✔ 最佳答案
51 g / 1.045 g/mL = volume of the solution. 41.80 mL* 2 mole/L = 0.0976 moles of LiCl (with some unit conversions). Convert moles of LiCl to mass.
Mass of water = 51 g - mass of LiCl
2016-06-13 1:56 pm
Volume of the solution = (51.0 g) / (1.0450 g/mL) = 51.0/1.0450 mL
No. of moles of LiCl = (2.00 mol/L) × [(51.0/1.0450) × (1/1000) L] = 0.0976 mol
Molar mass of LiCl = (6.94 + 35.45) g/mol = 42.39 g/mol
Mass of LiCl = (42.39 g/mol) × (0.0976 mol) = 4.14 g
Mass of H₂O = (51.0 - 4.14) g = 46.86 g
No. of moles of LiCl = (2.00 mol/L) × [(51.0/1.0450) × (1/1000) L] = 0.0976 mol
Molar mass of LiCl = (6.94 + 35.45) g/mol = 42.39 g/mol
Mass of LiCl = (42.39 g/mol) × (0.0976 mol) = 4.14 g
Mass of H₂O = (51.0 - 4.14) g = 46.86 g
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