calculate the molarity of each of the following solutions:?

molarity is the moles of the solute / the volume of the solution in L

100 mL = 0.1 L. 0.49 moles / 0.1 L = 4.9 moles/L = 4.9 M

Repeat for the others.

0.49 mole of BaCl₂ in 100.0 mL of solution

Molarity = (0.49 mol) / (100.0/1000 L) = 4.9 M


====
0.175 mole of Na₂CO₃ in 200.0 mL in solution

Molarity = (0.175 mol) / (200.0/1000 L) = 0.875 M


====
0.325 mole of C₆H₁₂O₆ in 250.0 mL of solution

Molarity = (0.325 mol) / (250.0/1000 L) = 1.30 M


====
1.494 mole of KNO₃ in 250.0 mL of solution

Molarity = (1.494 mol) / (250.0/1000) = 5.976 M