Electro chemistry help!?

2016-06-12 9:48 pm
In this redox equation below, which is the oxidizing agent ?

KMnO4 + HCl -> KCl +MnCl2 +Cl2 + H2O

回答 (2)

2016-06-12 9:51 pm
✔ 最佳答案
The oxidation number of Mn decreases from +7 (in KMnO₄) to +2 (in MnCl₂).

Hence, KMnO₄ is reduced and it acts as an oxidizing agent.
2016-06-12 10:57 pm
2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 5 Cl2 + 8 H2O

d) +7 to +2


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