Find an angle in third quadrant for which tan(theta)=1?
回答 (3)
2016-06-12 8:51 pm
When θ is in the first quadrant and tanθ = 1,
then θ = 45°
When θ is in the third quadrant and tanθ = 1,
then θ = (180° + 45°)
θ = 225°
then θ = 45°
When θ is in the third quadrant and tanθ = 1,
then θ = (180° + 45°)
θ = 225°
2016-06-12 8:46 pm
hint : tan π / 4 = 1 and tangent has period π
2016-06-12 8:45 pm
Well,
tan( 5pi/4 ) = 1
5pi/4 is in Quadrant 3
hope it' ll help !!
tan( 5pi/4 ) = 1
5pi/4 is in Quadrant 3
hope it' ll help !!
收錄日期: 2021-04-18 14:59:09
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