help with finding what is oxidized and reduced in these formulas?

It should be "equations" instead of "formulas".

1)
The equation for the reaction of calcium metal with hydrochloric acid is :
Ca(s) + 2HCl(aq) → CaCl₂(aq) + H₂(g)
Ca is oxidized as the oxidation number of Ca increases from 0 (in Ca) to +2 (in CaCl₂).
HCl is reduced as the oxidation number of H decreases from +1 (in HCl) to 0 (in H₂).

2)
The equation for the reaction of sodium metal with water is :
2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)
Na is oxidized as the oxidation number of Na increases from 0 (in Na) to +1 (in NaOH).
H₂O is reduced as the oxidation number of H decreases from +1 (in H₂O) to 0 (in H₂).

1)
Ca is oxidized and is the reducing agent.
H is reduced and so HCl is the oxidizing agent.

2)
Na is oxidized and is the reducing agent.
H is reduced and so H2O is the oxidizing agent.