What is the value of the equilibrium constant for the reaction below?
C + 2D <----> A + 1/2B
The value of the equilibrium constant for the following reaction is 3.4 x 10^5. 2A + B <---> 2C + 4D?
2016-06-12 3:02 pm
回答 (1)
2016-06-12 7:04 pm
✔ 最佳答案
2A + B ⇌ 2C + 4D ...... K = [C]²[D]⁴/[A]²[B] = 3.5 × 10⁵A + (1/2)B ⇌ C + 2D ...... K = [C][D]²/[A][B]⁰·⁵ = √(3.5 × 10⁵)
C + 2D ⇌ A + (1/2)B ...... K = [A][B]⁰·⁵/ [C][D]² = 1/√(3.5 × 10⁵) = 1.7 × 10⁻³
收錄日期: 2021-04-18 14:59:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160612070256AArHy0e