A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment.?
2016-06-10 2:38 pm
How many grams of Na3PO4 will be needed to produce 700mL of a solution that has a concentration of Na ions of 0.800M
回答 (2)
2016-06-17 3:08 pm
✔ 最佳答案
Calculate moles of Na^ ion: moles Na^ = V in liters x molarity = (0.700 L)(0.800 mol/L) = 0.560 mole Na^ ion
Now calculate the moles of Na3PO4 needed to provide this concentration of Na^ ion.
moles Na3PO4 = 0.560 mole Na^ (1 mol Na3PO4)/(3 mol Na^ ) = 0.187 mol Na3PO4
formula mass Na3PO4 = 163.94 g/mol
mass Na3PO4 needed = moles Na3PO4 x formula mass = (0.187 mol)(163.94 g/mol)
mass Na3PO4 = 30.60 g
Hope this is helpful to you. JIL HIR
2016-06-10 5:29 pm
From Wikipedia : Molar mass of Na₃PO₄ = 163.94 g/mol
No. of moles of Na⁺ ions = (0.800 mol/L) × (700/1000) = 0.560 mol
1 mole of Na₃PO₄ gives 3 moles of Na⁺ ions.
No. of moles of Na₃PO₄ = 0.560/3 mol
Mass of Na₃PO₄ = (163.94 g/mol) × (0.560/3 mol) = 30.6 g
No. of moles of Na⁺ ions = (0.800 mol/L) × (700/1000) = 0.560 mol
1 mole of Na₃PO₄ gives 3 moles of Na⁺ ions.
No. of moles of Na₃PO₄ = 0.560/3 mol
Mass of Na₃PO₄ = (163.94 g/mol) × (0.560/3 mol) = 30.6 g
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