what is the mass of 10.2 L of ammonia (NH3) at stp?

2016-06-10 3:05 am

回答 (2)

2016-06-10 3:11 am
From Wikipedia : Molar mass of NH₃ = 17.031 g/mol
Molar volume of NH₃ at STP = 22.4 L/mol

No. of moles of NH₃ = (10.2 L) / (22.4 L/mol) = 10.2/22.4 mol
Mass of NH₃ = (10.2/22.4 mol) × (17.031 g/mol) = 7.76 g
2016-06-10 3:14 am
one mole of NH3 at STP occupies 22.414 L

10.2 L / 22.44 L/mol = 0.45507 mol

0.45507 mol times 17.0307 g/mol = 7.75 g

Or, you can use PV = nRT

and calculate moles, then multiply by the molar mass.

Using 22.414 works only at STP, using PV = nRT works at any T and P.


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