Maths,答案加步驟?

2016-06-08 3:06 am
1) Find the center and radius of the circle 4x^2+4y^2-7x-8y=2
2a) Find the center and radius of the circle 2x^2+2y^2-16x+12y-48=0
2b) Determine whether the points P(-5,2) lie inside, outside or on the circle in part (a)

回答 (2)

2016-06-08 5:37 am
✔ 最佳答案
1) Find the center and radius of the circle 4x^2+4y^2-7x-8y=2
Sol
4x^2+4y^2-7x-8y=2
(4x^2-7x)+(4y^2-8y)=2
(x^2-7x/4)+(y^2-2y)=1/2
(x^2-7x/4+49/64)+(y^2-2y+1)=49/64+1+1/2
(x-7/8)^2+(y-1)^2=145/64
圓心:(7/8,1),半徑=√145/8
2a) Find the center and radius of the circle 2x^2+2y^2-16x+12y-48=0
Sol
2x^2+2y^2-16x+12y-48=0
(x^2-8x)+(y^2+6y)=24
(x^2-8x+16)+(y^2+6y+9)=24+16+9
(x-4)^2+(y+3)^2=7^2
圓心:(4,-3),半徑=7
2b) Determine whether the points P(-5,2) lie inside, outside or on the circle in part (a)
d^2=[4-(-5)]^2+(-3-2)^2=81+25=106>49
outside
2016-07-05 2:38 pm
1.
4x^2+4y^2-7x-8y=2
x^2+y^2-7/4 x-2y-0.5=0
center=(7/8,1)
radius=[(7/8)^2 +(1)^2 +0.5]^0.5
radius=(145^0.5)/8
(x-7/8)^2 +(y-1)=145/64

2a)
2x^2+2y^2-16x+12y-48=0
center=(4,-3)
radius=7
(x-4)^2 +(y+3)^2=7^2

2b
(-5-4)^2 +(2-3)^2
=82>49
outside the circle


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