Can someone help simplify this? I posted a picture so the equation is more clear. I'm not sure if I typed this equation correctly.
y=1/4log2(8x-56)^16-12
pic of equation: http://imgur.com/1GEBIFP
simplifying logarithm?
2016-06-07 7:02 pm
回答 (2)
2016-06-07 7:08 pm
y = ¼log₂((8x-56)¹⁶) - 12
= log₂(∜(8x-56)¹⁶) - 12
= log₂((8x-56)⁴) - 12
= log₂((8(x-7))⁴) - 12
= log₂(8⁴(x-7)⁴) - 12
= log₂(8⁴) + log₂((x-7)⁴) - 12
= log₂(2¹²) + log₂((x-7)⁴)
= 12 + log₂((x-7)⁴) - 12
= log₂((x-7)⁴)
= 4log₂(x-7)
= log₂(∜(8x-56)¹⁶) - 12
= log₂((8x-56)⁴) - 12
= log₂((8(x-7))⁴) - 12
= log₂(8⁴(x-7)⁴) - 12
= log₂(8⁴) + log₂((x-7)⁴) - 12
= log₂(2¹²) + log₂((x-7)⁴)
= 12 + log₂((x-7)⁴) - 12
= log₂((x-7)⁴)
= 4log₂(x-7)
2016-06-07 7:52 pm
y= 1/4 log2(8x - 56)^16 -12
from log 10 to log 2, multiplied by log 2(10).
from log 2 to log 10, divided by log 2(10).
log2(10) = 3.01
Therefore,
y= 1/4 log ((8x-56)^16/3.01) -12
(The another answer came from D.W.,
where 4log2(x-7) can be converted to another number of log base 10)
Divide x-7 by 3.01, where log2(10) = 3.01.
4log2(x-7) = 4log((x-7)/3.01)
from log 10 to log 2, multiplied by log 2(10).
from log 2 to log 10, divided by log 2(10).
log2(10) = 3.01
Therefore,
y= 1/4 log ((8x-56)^16/3.01) -12
(The another answer came from D.W.,
where 4log2(x-7) can be converted to another number of log base 10)
Divide x-7 by 3.01, where log2(10) = 3.01.
4log2(x-7) = 4log((x-7)/3.01)
收錄日期: 2021-05-01 21:04:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160607110228AAmaMf8