Let f(x)= x^2+5 and g(x)= x+5/x find (g of f) (-3)?
回答 (4)
2016-06-07 4:28 pm
Case I : f(x) = x² + 5 and g(x) = x + (5/x)
g(f(-3))
= g((-3)² + 5)
= g(14)
= 14 + (5/14)
= 201/14
====
Case II: f(x) = x² + 5 and g(x) = (x + 5)/x
g(f(-3))
= g((-3)² + 5)
= g(14)
= (14 + 5)/14
= 19/14
g(f(-3))
= g((-3)² + 5)
= g(14)
= 14 + (5/14)
= 201/14
====
Case II: f(x) = x² + 5 and g(x) = (x + 5)/x
g(f(-3))
= g((-3)² + 5)
= g(14)
= (14 + 5)/14
= 19/14
2016-06-07 4:37 pm
x is minus 3. because f(-3) means substitute x=-3.
then calculate g(x) when x= -3.
then calculate g(x) when x= -3.
2016-06-07 4:55 pm
(g∘f)(-3) = g(f(-3))
= g((-3)²+5)
= g(14)
= (14+5)/14
= 19/14
= g((-3)²+5)
= g(14)
= (14+5)/14
= 19/14
2016-06-07 4:13 pm
bebe become doctor
收錄日期: 2021-04-18 14:58:31
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