A sample of an ideal gas has a volume of 3.70 L at 12.80 °C and 1.80 atm. What is the volume of the gas at 23.00 °C and 0.996 atm? In L?
回答 (1)
2016-06-07 11:39 am
Initial: P₁ = 1.80 atm, V₁ = 3.7 L, T₁ = (273.15 + 12.80) K = 285.95 K
Final: P₂ = 0.996 atm, V₂ = ? L, T₂ = (273.15 + 23.00) K = 296.15 K
P₁V₁/T₁ = P₂V₂/T₂
V₂ = V₁ × (P₁/P₂) × (T₂/T₁)
Final volume, V₂ = (3.70 L) × (1.80/0.996) × (296.15/285.95) = 6.93 L
Final: P₂ = 0.996 atm, V₂ = ? L, T₂ = (273.15 + 23.00) K = 296.15 K
P₁V₁/T₁ = P₂V₂/T₂
V₂ = V₁ × (P₁/P₂) × (T₂/T₁)
Final volume, V₂ = (3.70 L) × (1.80/0.996) × (296.15/285.95) = 6.93 L
收錄日期: 2021-04-18 14:57:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160606185323AAUuxr6