If 25.0mL of .100mol/L CrCl2(aq) was required to completely consume 13.5mL of K₂Cr₂O₇(aq), calculate the initial concentration of the K₂Cr₂O₇(aq).
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Chemistry Redox Question Help?
2016-06-07 2:12 am
回答 (1)
2016-06-07 11:56 am
K₂Cr₂O₇ + 14 HCl → 2 KCl + 2 CrCl₂ + 7 H₂O + 4 Cl₂
Mole ratio K₂Cr₂O₇ : CrCl₂ = 1 : 2
No. of moles of CrCl₂ = (0.100 mol/L) × (25.0/1000) = 0.0025 mol
No. of moles of K₂Cr₂O₇ = (0.0025 mol) × (1/2) = 0.00125 mol
Initial concentration of K₂Cr₂O₇ = (0.00125 mol) / (13.5/1000 L) = 0.0926 mol/L
Mole ratio K₂Cr₂O₇ : CrCl₂ = 1 : 2
No. of moles of CrCl₂ = (0.100 mol/L) × (25.0/1000) = 0.0025 mol
No. of moles of K₂Cr₂O₇ = (0.0025 mol) × (1/2) = 0.00125 mol
Initial concentration of K₂Cr₂O₇ = (0.00125 mol) / (13.5/1000 L) = 0.0926 mol/L
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