2z^3-6z^2/z^2-3z?
回答 (4)
2016-05-31 5:05 pm
(2z³ - 6z²) / (z² - 3z)
= [2z²(z - 3)] / [z(z - 3)]
= 2z
= [2z²(z - 3)] / [z(z - 3)]
= 2z
2016-05-31 9:52 pm
2z² [ z - 3 ]
------------------ = 2
z [ z - 3 ]
------------------ = 2
z [ z - 3 ]
2016-05-31 5:12 pm
(2z^3 - 6z^2) / (z^2 - 3z)
= 2z^2(z - 3) / z(z - 3)
= 2z
= 2z^2(z - 3) / z(z - 3)
= 2z
2016-05-31 5:04 pm
If that is:
(2z³ - 6z²) / (z² - 3z)
Then the first thing that I'll do is pull out the common factors. 2z² in the numerator and z in the denominator:
2z²(z - 3) / [z(z - 3)]
Now we can cancel out our common factors, z and (z - 3) to leave this as our answer:
2z
(2z³ - 6z²) / (z² - 3z)
Then the first thing that I'll do is pull out the common factors. 2z² in the numerator and z in the denominator:
2z²(z - 3) / [z(z - 3)]
Now we can cancel out our common factors, z and (z - 3) to leave this as our answer:
2z
收錄日期: 2021-04-18 14:56:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160531090140AAqNQCu