A mixture consisting of 0.150 M N2(g) and 0.744 M H2(g) reacts and then reaches equilibrium according to the equation:
N2(g) + 3H2(g) ⇋ 2NH3(g)
At equilibrium, the concentration of ammonia is 0.235 M. Calculate the concentration (molarity) of H2(g) at equilibrium to 3 decimal places.
Chemistry Equilibrium question, please help!?
2016-05-31 10:50 am
回答 (1)
2016-05-31 11:04 am
✔ 最佳答案
N₂(g) + 3H₂(g) ⇌ 2NH₃(g)Mole ratio H₂ : NH₃ = 3 : 2
No. of moles of NH₃ formed = 0.235 mol/L
No. of moles of H₂ reacted = (0.235 mol/L) × (3/2)
Equilibrium concentration of H₂ = [0.744 - 0.235 × (3/2)] mol/L = 0.392 mol/L
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